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Legen Sie ein privates Mitglied einer Klasse als Konstruktorparameter fest

P粉761718546 2024-04-06 21:48:47

1826

class Foo {
  #one
  #two
  #three
  #four
  #five
  #six
  #seven
  #eight
  #nine
  #ten
  #eleven
  #twelve
  #thirteen
  #fourteen
  #fifteen
  #sixteen

  constructor(
    one,
    two,
    three,
    four,
    five,
    six,
    seven,
    eight,
    nine,
    ten,
    eleven,
    twelve,
    thirteen,
    fourteen,
    fifteen,
    sixteen
  ) {
    this.#one = one;
    this.#two = two;
    this.#three = three;
    this.#four = four;
    this.#five = five;
    this.#six = six;
    this.#seven = seven;
    this.#eight = eight;
    this.#nine = nine;
    this.#ten = ten;
    this.#eleven = eleven;
    this.#twelve = twelve;
    this.#thirteen = thirteen;
    this.#fourteen = fourteen;
    this.#fifteen = fifteen;
    this.#sixteen = sixteen;
  }
}

Was ist die L?sung für dieses (Anti-?)Muster?

P粉761718546

Antworte allen(1)

P粉0109671362024-04-07 12:15:44 1 Etage

對(duì)于任何想要使用構(gòu)造函數(shù)的人來(lái)說(shuō)，擁有 16 個(gè)參數(shù)并不有趣。您在評(píng)論中提出的配置對(duì)象想法要有趣得多，當(dāng)然，當(dāng)您將其與擁有一個(gè)具有所有這些屬性的類型對(duì)象的私有屬性的想法結(jié)合起來(lái)時(shí)。然后您可以使用 Object.assign 來(lái)根據(jù)用戶的首選項(xiàng)更新它：

class Foo {
  #options = {
    one: 1,
    two: 2,
    three: 3,
    four: 4
  }
  constructor(options = {}) {
    Object.assign(this.#options, options);
    console.log(this.#options);
  }
}

let foo = new Foo({three: 3000});