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我正在嘗試在Fixtures類(lèi)別中自動(dòng)組裝PasswordHasherInterface：

<?php
namespace AppDataFixtures;

use AppModelUserEntityUserEmail;
use AppModelUserEntityUserId;
use AppModelUserEntityUserRole;
use AppModelUserEntityUserUser;
use DoctrineBundleFixturesBundleFixture;
use DoctrinePersistenceObjectManager;
use SymfonyComponentPasswordHasherPasswordHasherInterface;

class UserFixture extends Fixture
{
    private PasswordHasherInterface $hasher;

    public function __construct(PasswordHasherInterface $hasher)
    {
        $this->hasher = $hasher;
    }
    
    public function load(ObjectManager $manager): void
    {
        $hash = $this->hasher->hash("password");

        $user = User::signUpByEmail(
            Id::next(),
            new DateTimeImmutable(),
            new Email("admin@app.test"),
            $hash,
            "token"
        );

        $user->confirmSignUp();

        $user->changeRole(Role::admin());

        $manager->persist($user);
        $manager->flush();
    }
}

但是我得到了錯(cuò)誤：

在 DefinitionErrorExceptionPass.php 第 54 行： ！ ！

!!無(wú)法自動(dòng)組裝服務(wù)「AppDataFixturesUserFixture」：參數(shù)「$hasher」

# !!方法「__construct()」引用介面「SymfonyComponentPasswordH

# !! asherPasswordHasherInterface”，但不存在此類(lèi)服務(wù)。您是否創(chuàng)建了

# !!實(shí)作這個(gè)介面的類(lèi)別？

！ ！

我的檔案 services.yaml：

parameters:

services:
    # default configuration for services in *this* file
    _defaults:
        autowire: true      # Automatically injects dependencies in your services.
        autoconfigure: true # Automatically registers your services as commands, event subscribers, etc.

    # makes classes in src/ available to be used as services
    # this creates a service per class whose id is the fully-qualified class name
    App:
        resource: '../src/'
        exclude:
            - '../src/DependencyInjection/'
            - '../src/Model/User/Entity/'
            - '../src/Kernel.php'

如何在 Symfony 6.1 中散列純密碼？ 為什麼我會(huì)收到此錯(cuò)誤？