class Foo {
#one
#two
#three
#four
#five
#six
#seven
#eight
#nine
#ten
#eleven
#twelve
#thirteen
#fourteen
#fifteen
#sixteen
constructor(
one,
two,
three,
four,
five,
six,
seven,
eight,
nine,
ten,
eleven,
twelve,
thirteen,
fourteen,
fifteen,
sixteen
) {
this.#one = one;
this.#two = two;
this.#three = three;
this.#four = four;
this.#five = five;
this.#six = six;
this.#seven = seven;
this.#eight = eight;
this.#nine = nine;
this.#ten = ten;
this.#eleven = eleven;
this.#twelve = twelve;
this.#thirteen = thirteen;
this.#fourteen = fourteen;
this.#fifteen = fifteen;
this.#sixteen = sixteen;
}
}
這個（反？）模式的解決方案是什麼？
1
0
0
對於任何想要使用建構(gòu)函數(shù)的人來說，擁有 16 個參數(shù)並不有趣。您在評論中提出的配置對像想法要有趣得多，當(dāng)然，當(dāng)您將其與擁有具有所有這些屬性的類型對象的私有屬性的想法結(jié)合起來時。然後您可以使用 Object.assign 來根據(jù)使用者的首選項更新它：
class Foo {
#options = {
one: 1,
two: 2,
three: 3,
four: 4
}
constructor(options = {}) {
Object.assign(this.#options, options);
console.log(this.#options);
}
}
let foo = new Foo({three: 3000});
