


Why Does My PHP Random Password Generator Only Produce \'a\'s and an Array?
Nov 26, 2024 pm 01:59 PMGenerating a Random String for Password in PHP
Problem:
When generating a random password in PHP using the code snippet below, all characters are 'a's, and the return value is an array instead of a string.
function randomPassword() { $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789"; for ($i = 0; $i < 8; $i++) { $n = rand(0, count($alphabet)-1); $pass[$i] = $alphabet[$n]; } return $pass; }
Solution:
1. Use strlen instead of count to calculate the length of the alphabet: count always returns 1 for a string, while strlen returns the actual length.
$alphaLength = strlen($alphabet) - 1; //put the length -1 in cache
2. Use implode to convert the array to a string: implode takes an array and joins its elements into a single string.
return implode($pass); //turn the array into a string
3. Declare $pass as an array: This prevents it from being initialized as a string.
$pass = array(); //remember to declare $pass as an array
Security Warning:
Note that rand() is not a cryptographically secure pseudorandom number generator. Consider using more secure alternatives for generating passwords or cryptographic purposes.
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