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Table of Contents
The variable defined inside the function is local
Want to change global variables in a function? Use global
Want to modify outer non-global variables in nested functions? Use nonlocal
Home Backend Development Python Tutorial Understanding Python scope: local, global, nonlocal

Understanding Python scope: local, global, nonlocal

Jul 09, 2025 am 02:31 AM

Python scope is prone to causing variable errors, and the key is to understand the use of local, global and nonlocal. 1. The variable assigned with = in the function is local by default, even if the same name as the global variable does not affect each other; 2. Only external variables are read without declaration, but global variables are required to be declared when modifying, otherwise local variables will be created; 3. Nonlocal is required to modify outer non-global variables in nested functions, indicating that the most recent outer variable is used, and cannot be cross-level or used for global variables. Mastering these rules can effectively avoid variable reference errors.

Understanding Python scope: local, global, nonlocal

Python's scope looks simple, but many people will encounter problems such as variables not being found or assignment errors when actually writing code. The key is to figure out when and which variable is used, especially the usage scenarios of local , global and nonlocal keywords.

Understanding Python scope: local, global, nonlocal

The variable defined inside the function is local

When you use = to assign a value to a variable in a function, the variable is a local variable by default. Even if you define a variable with the same name outside the function, the global variable will not be automatically used inside the function.

For example:

Understanding Python scope: local, global, nonlocal
 x = 10

def func():
    x = 5
    print(x)

func() # Output 5
print(x) # Output 10

At this time, x in the function and x outside are two different variables. If you just read the external variable without modifying it, it is accessible:

 x = 10

def read_x():
    print(x)

read_x() # Output 10

But as long as you try to assign a value to x in a function, such as x = ... , Python will treat it as a local variable unless you specifically specify it.

Understanding Python scope: local, global, nonlocal

Want to change global variables in a function? Use global

If you really want to change the value of a global variable in a function, you must declare it global :

 x = 10

def change_global():
    global x
    x = 20

change_global()
print(x) # Output 20

If global is not added, it will become the situation mentioned above: a local variable x is created in the function, which will not affect the outside.

Common errors are written like this:

 x = 10

def bad_func():
    x = 1 # An error will be reported here UnboundLocalError

Because x = 1 is equivalent to x = x 1 , and global x is not declared in the function, Python thinks that you are operating on local variables, but you have not assigned a value at this time, and you have an error.


Want to modify outer non-global variables in nested functions? Use nonlocal

If there are functions (nested functions) in the function, if you want to modify the variables of the outer function, you must use nonlocal .

See an example:

 def outer():
    x = 10
    def inner():
        nonlocal x
        x = 20
    inner()
    print(x) # Output 20

outer()

Here, nonlocal x is used in inner() , telling Python that I want to use the x closest to me that is not global, that is, the one in outer() . If nonlocal is not added, then x = 20 will create a new local variable in inner() , which has no effect on the outer layer.

A few points to note:

  • nonlocal can only be used in nested functions and cannot be used to modify global variables
  • The referenced variable must already exist in the outer scope and cannot be found "cross-level".
  • If there is no corresponding variable in the outer layer, an error will be reported

Basically that's it. Understanding the difference between local, global, and nonlocal can avoid many inexplicable bugs. Especially when writing closures or multi-layer nested functions, remember to check whether the variable is the one you want.

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