1. Trying to imitate a login program. This login form is on the home page. After successful login, it is required to use ajax on the home page to return the user name information (saved session value) without refreshing and automatically hide the form. Now it is true that user information can be returned through js, but as long as it is refreshed, the user information and form will be restored to their original state. How can it be maintained for a long time until the user clicks to log out or the session disappears?
2. I can see the returned user information through the xhr mode of F12. It can also be achieved through the append method and remove() of jquery. However, the problem is that the information does not exist and the form returns to its original state after refreshing.
2. Key code:
(1) IndexController.class.php:

<code>public function checkUser(){
    //接收值
    $userName=$_POST['username'];
    $userPass=$_POST['userpass'];
    //空值檢測(cè)->function
    if(!trim($userName)){
      return show(0,'用戶名不能為空');
    }
    if(!trim($userPass)){
      return show(0,'密碼不能為空');
    }
    //對(duì)用戶密碼真實(shí)性進(jìn)行檢驗(yàn)->Model
    $res=D("Stuser")->getUser($userName);
    if(!$res['username']){
      return show(0,'用戶名不存在');
    }
    //密碼處理->function
    if($res['userpass']!=getMd5Pass($userPass)){
      return show(0,'密碼不正確');
    }
    //echo $res['username'];
    //$_SESSION('username',$res);  //設(shè)置session
    $_SESSION['username']=$res;
    //dump($username) ;
    //var_dump($username);
    return show(1,'登錄成功',$this->getSessionNames());
  }
  //判斷session情況->index
  public function getSessionNames(){
    if($_SESSION['username']['username']){
      $username = $_SESSION['username']['username'];
      //$a=$this->ajaxReturn($username);
      //$this->assign('username',$username);
      return $username;
    }
  }請(qǐng)輸入代碼</code>

(2)function.php

<code>function show($status,$message,$data=array()){
    $result=array(
      'status' => $status,
      'message' => $message,
      'data' => $data,
    );
    //JSON編碼數(shù)據(jù)
    exit(json_encode($result));
  }請(qǐng)輸入代碼</code>

(3) login.js

<code>var login = {
  checkUser : function() {
      //獲取登錄頁面中的用戶名、密碼
      var userName=$('input[name="username"]').val();
      var userPass=$('input[name="userpass"]').val();

      if(!userName) {
        dialog.error("用戶名不能為空");
      }

      if(!userPass) {
        dialog.error("密碼不能為空");
      }

      var url="/stfjzd-12/index.php/Home/Index/checkUser";
      var data={'username':userName,'userpass':userPass};
      //執(zhí)行異步請(qǐng)求
      $.post(url,data,function(result){
        if(result.status==0) {
            return dialog.error(result.message);
        }
        if(result.status==1) {
        if(data!=""){
            //alert(data.username);
            $('#index_form2').remove();
            $('#test').append(data.username);
        }
            return dialog.success(result.message,"/stfjzd-12/index.php/Home/Index/checkUser");
        //alert(result.data['username']) ;
        }
      },'JSON');

  }
}請(qǐng)輸入代碼</code>

Reply content:

1. Trying to imitate a login program. This login form is on the home page. After successful login, it is required to use ajax on the home page to return the user name information (saved session value) without refreshing and automatically hide the form. Now it is true that user information can be returned through js, but as long as it is refreshed, the user information and form will be restored to their original state. How can it be maintained for a long time until the user clicks to log out or the session disappears?
2. I can see the returned user information through the xhr mode of F12. It can also be achieved through the append method and remove() of jquery. However, the problem is that the information does not exist and the form returns to its original state after refreshing.
2. Key code:
(1) IndexController.class.php:

<code>public function checkUser(){
    //接收值
    $userName=$_POST['username'];
    $userPass=$_POST['userpass'];
    //空值檢測(cè)->function
    if(!trim($userName)){
      return show(0,'用戶名不能為空');
    }
    if(!trim($userPass)){
      return show(0,'密碼不能為空');
    }
    //對(duì)用戶密碼真實(shí)性進(jìn)行檢驗(yàn)->Model
    $res=D("Stuser")->getUser($userName);
    if(!$res['username']){
      return show(0,'用戶名不存在');
    }
    //密碼處理->function
    if($res['userpass']!=getMd5Pass($userPass)){
      return show(0,'密碼不正確');
    }
    //echo $res['username'];
    //$_SESSION('username',$res);  //設(shè)置session
    $_SESSION['username']=$res;
    //dump($username) ;
    //var_dump($username);
    return show(1,'登錄成功',$this->getSessionNames());
  }
  //判斷session情況->index
  public function getSessionNames(){
    if($_SESSION['username']['username']){
      $username = $_SESSION['username']['username'];
      //$a=$this->ajaxReturn($username);
      //$this->assign('username',$username);
      return $username;
    }
  }請(qǐng)輸入代碼</code>

(2)function.php

<code>function show($status,$message,$data=array()){
    $result=array(
      'status' => $status,
      'message' => $message,
      'data' => $data,
    );
    //JSON編碼數(shù)據(jù)
    exit(json_encode($result));
  }請(qǐng)輸入代碼</code>

(3) login.js

<code>var login = {
  checkUser : function() {
      //獲取登錄頁面中的用戶名、密碼
      var userName=$('input[name="username"]').val();
      var userPass=$('input[name="userpass"]').val();

      if(!userName) {
        dialog.error("用戶名不能為空");
      }

      if(!userPass) {
        dialog.error("密碼不能為空");
      }

      var url="/stfjzd-12/index.php/Home/Index/checkUser";
      var data={'username':userName,'userpass':userPass};
      //執(zhí)行異步請(qǐng)求
      $.post(url,data,function(result){
        if(result.status==0) {
            return dialog.error(result.message);
        }
        if(result.status==1) {
        if(data!=""){
            //alert(data.username);
            $('#index_form2').remove();
            $('#test').append(data.username);
        }
            return dialog.success(result.message,"/stfjzd-12/index.php/Home/Index/checkUser");
        //alert(result.data['username']) ;
        }
      },'JSON');

  }
}請(qǐng)輸入代碼</code>

If you write it in TP and use {$Think.session.username} in the template, the refresh through js assignment will definitely be gone

Just create a hidden field on the page to put the information. The session information on the page will only be requested after you log in successfully. Refreshing the page will not trigger the request

<code>public function index(){ //你顯示頁面的函數(shù)
    $user=$this->getSessionNames();
    $this->assing('user',$user);
    ...
}</code>

<code>//index.html
<script>
    $(function(){
        var username="{{$user}}";
        if(username != ""){
            $('#index_form2').remove();
            $('#test').append(username);
        }
    })
    
</script></code>

<code> //login.js</code>

The poster’s question doesn’t seem to be difficult at all! Just make the form where you store user information dynamic, as follows:

<code>//這個(gè)是php的處理代碼塊
if($this->chen_user()) {   //這個(gè)是驗(yàn)證是否登陸成功
    $_SESSION['username'] = $username;  //這里把用戶信息存入session
    $_SESSION['sex] = $sex;
}

//這個(gè)是前端顯示的
<?php 
if($_SESSION['username']) { ?>  如果session中有username的值就輸出用戶信息 沒有就不輸出
    <td>姓名</td><td><?php echo $_SESSION['username'];?></td>

<?php } ?></code>

Do you think this is the case?