sqlite
database; ??? ??? ??????
having
English ['h?v?y?]
n. Have(have? ?? ??) ; ?? ????) ??
SQLiteHaving?? ???
Role: HAVING ?? ???? ?? ??? ??? ???? ??? ????? ??? ??? ? ????.
WHERE ?? ??? ?? ?? ??? ????, HAVING ?? GROUP BY ?? ?? ??? ???? ?? ??? ?????.
??: ????? SELECT ???? HAVING ?? ?????.
SELECT
FROM
WHERE
GROUP BY
HAVING
ORDER BY
???? HAVING ?? GROUP? ????? ???. BY ? ???? ORDER BY ? ?? ?? ???. HAVING ?? ??? SELECT ?? ??? ??? ????.
SELECT column1, column2
FROM table1, table2
WHERE [??]
GROUP BY ??1, ??2
HAVING [??]
ORDER BY ??1, ??2
SQLiteHaving?? ?
COMPANY 表有以下記錄: ID NAME AGE ADDRESS SALARY ---------- ---------- ---------- ---------- ---------- 1 Paul 32 California 20000.0 2 Allen 25 Texas 15000.0 3 Teddy 23 Norway 20000.0 4 Mark 25 Rich-Mond 65000.0 5 David 27 Texas 85000.0 6 Kim 22 South-Hall 45000.0 7 James 24 Houston 10000.0 8 Paul 24 Houston 20000.0 9 James 44 Norway 5000.0 10 James 45 Texas 5000.0 下面是一個實例,它將顯示名稱計數(shù)小于 2 的所有記錄: sqlite > SELECT * FROM COMPANY GROUP BY name HAVING count(name) < 2; 這將產(chǎn)生以下結(jié)果: ID NAME AGE ADDRESS SALARY ---------- ---------- ---------- ---------- ---------- 2 Allen 25 Texas 15000 5 David 27 Texas 85000 6 Kim 22 South-Hall 45000 4 Mark 25 Rich-Mond 65000 3 Teddy 23 Norway 20000 下面是一個實例,它將顯示名稱計數(shù)大于 2 的所有記錄: sqlite > SELECT * FROM COMPANY GROUP BY name HAVING count(name) > 2; 這將產(chǎn)生以下結(jié)果: ID NAME AGE ADDRESS SALARY ---------- ---------- ---------- ---------- ---------- 10 James 45 Texas 5000