


Why Does Template Member Function Invocation Within a Template Function Fail in C ?
Nov 02, 2024 am 02:57 AMTemplate Member Function Invocation within Template Function
In the given code, an attempt to invoke a template member function f within a template function g fails with compilation errors:
<code class="cpp">template<class X> struct A { template<int I> void f() {} }; template<class T> void g() { A<T> a; a.f<3>(); // Compilation fails here (Line 18) }</code>
According to the C Standard (14.2/4), when a member template specialization is called after a ., the template keyword must be explicitly specified to differentiate it from a non-template member function.
To resolve the compilation error, the code should be modified as follows:
<code class="cpp">template<class T> void g() { A<T> a; a.template f<3>(); // add `template` keyword here }</code>
By adding the template keyword, the compiler recognizes that the invoked function is a member template specialization, resolving the ambiguity and allowing the code to compile successfully.
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