Is C# Static Class Initialization Order Deterministic and Predictable?
Jan 04, 2025 am 12:43 AMIs Static Class Initialization Order in C# Predictable?
In C#, static class members are initialized in a deterministic order. This behavior is crucial to understand, as it can affect the outcome of your code, especially in situations involving circular dependencies between static members.
Initialization Sequence
According to the C# language specification (ECMA-334), the order of static class initialization is as follows:
- Execution of static field initializers (in textual order)
- Execution of the static constructor
This sequence ensures that all static fields are initialized before the static constructor is invoked.
Example
Consider the following code:
static class B { public static int X = 7; static B() { ... } } static class A { public static int X = B.X + 1; static A() { ... } } static class Program { static void Main() { ... } }
In this example, the initialization sequence is as follows:
- B.X is initialized to 7.
- A.X is initialized to B.X 1, which results in a default value since B.X has not yet been initialized.
- The static constructor of class B is invoked, and B.X is set to A.X, which is still the default value.
- The static constructor of class A is invoked, and A.X is set to B.X 1, which is now 1.
Therefore, the final values of A.X and B.X will be 1 and 0, respectively.
Implications
This predictable initialization order has important implications for coding practices. For instance, it emphasizes the importance of initializing static fields with explicit values, avoiding reliance on default values. Additionally, it ensures that static constructors are only executed once per class, even in scenarios with multiple references or instances.
By understanding this deterministic order, developers can write code that initializes and interacts with static members safely and efficiently.
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