Java program to delete all even nodes from a singly linked list
Feb 07, 2025 am 11:36 AMThis Java program efficiently removes all even-valued nodes from a singly linked list. Let's refine the explanation and presentation for clarity.
This article demonstrates how to remove all even-numbered nodes from a singly linked list in Java. We'll cover creating the list, adding nodes, deleting even-valued nodes, and displaying the final list.
A singly linked list is a linear data structure where each node points to the next node in the sequence. Each node contains data (in this case, an integer) and a pointer to the next node.
Problem: Delete all even-valued nodes from a singly linked list.
Input Example:
<code>Original List: 1 2 3 4 5 6</code>
Output Example:
<code>Original List: 1 2 3 4 5 6 List after deleting even nodes: 1 3 5</code>
Algorithm:
- Initialization: Create an empty singly linked list.
- Node Insertion: Add nodes with integer values (e.g., 1, 2, 3, 4, 5, 6) to the list.
-
Even Node Removal:
- Remove Leading Evens: Iterate from the head of the list, removing any even-valued nodes at the beginning until an odd-valued node is encountered.
-
Remove Internal Evens: Traverse the remaining list. If a node's
next
node has an even value, bypass it by linking the current node directly to the node after the even-valued node.
- Output: Print the remaining nodes in the list.
Java Code:
public class LinkedList { static class Node { int data; Node next; Node(int data) { this.data = data; this.next = null; } } Node head; public void insert(int data) { Node newNode = new Node(data); if (head == null) { head = newNode; } else { Node temp = head; while (temp.next != null) { temp = temp.next; } temp.next = newNode; } } public void deleteEvenNodes() { //Remove leading even nodes while (head != null && head.data % 2 == 0) { head = head.next; } //Remove internal even nodes if (head != null) { //Check if list is not empty after removing leading evens Node current = head; while (current != null && current.next != null) { if (current.next.data % 2 == 0) { current.next = current.next.next; } else { current = current.next; } } } } public void printList() { Node temp = head; while (temp != null) { System.out.print(temp.data + " "); temp = temp.next; } System.out.println(); } public static void main(String[] args) { LinkedList list = new LinkedList(); list.insert(1); list.insert(2); list.insert(3); list.insert(4); list.insert(5); list.insert(6); System.out.println("Original List:"); list.printList(); list.deleteEvenNodes(); System.out.println("List after deleting even nodes:"); list.printList(); } }
Output:
<code>Original List: 1 2 3 4 5 6 List after deleting even nodes: 1 3 5 </code>
This improved version includes a more concise explanation, clearer code comments, and handles the edge case where all nodes are even (resulting in an empty list). The addition of a check (if (head != null)
) before processing internal nodes prevents a NullPointerException
if all leading nodes were even.
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