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How do Static Method Calls Behave in ES6 Classes with Inheritance and Overriding?
How do Static Method Calls Behave in ES6 Classes with Inheritance and Overriding?
Nov 17, 2024 pm 05:28 PM
Calling Static Methods from ES6 Class Methods
In ES6 classes, there are two common ways to call static methods: through the constructor or through the class name itself. While both approaches are valid, they exhibit distinct behaviors in the context of inheritance with overridden static methods.
Using this.constructor to refer to the static property results in dynamic dispatch, which means it references the class of the current instance. This is useful when dealing with overridden static methods, as seen in the example below:
class Super {
static whoami() {
return "Super";
}
}
class Sub extends Super {
static whoami() {
return "Sub";
}
}
new Sub().whoami(); // "Sub"
In this case, the whoami static method is overridden in the Sub class. When called through this.constructor, it refers to the Sub class and correctly returns "Sub."
On the other hand, using the class name to refer to the static property ensures constant access to the original static method, even if it's overridden. For example:
class AnotherSuper {
static whoami() {
return "AnotherSuper";
}
}
class AnotherSub extends AnotherSuper {
static whoami() {
return "AnotherSub";
}
}
AnotherSub.whoami(); // "AnotherSuper"
Even though whoami is overridden in AnotherSub, calling it through the class name ("AnotherSub") still returns "AnotherSuper" because it refers to the static property of the AnotherSuper class.
Ultimately, the choice of which approach to use depends on the expected behavior. If the static property should always refer to the current class, use the explicit reference (this.constructor). Otherwise, use the class name to ensure constant access to the original static method.
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